2cos^2(x)+5cos(x)-3=0

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Solution for 2cos^2(x)+5cos(x)-3=0 equation:


Simplifying
2cos2(x) + 5cos(x) + -3 = 0

Multiply cos2 * x
2cos2x + 5cos(x) + -3 = 0

Multiply cos * x
2cos2x + 5cosx + -3 = 0

Reorder the terms:
-3 + 5cosx + 2cos2x = 0

Solving
-3 + 5cosx + 2cos2x = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 5cosx + 3 + 2cos2x = 0 + 3

Reorder the terms:
-3 + 3 + 5cosx + 2cos2x = 0 + 3

Combine like terms: -3 + 3 = 0
0 + 5cosx + 2cos2x = 0 + 3
5cosx + 2cos2x = 0 + 3

Combine like terms: 0 + 3 = 3
5cosx + 2cos2x = 3

Reorder the terms:
-3 + 5cosx + 2cos2x = 3 + -3

Combine like terms: 3 + -3 = 0
-3 + 5cosx + 2cos2x = 0

The solution to this equation could not be determined.

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